Q. What is the mass of one curie of $U^{234}$?
A) $3.7 \times 10^{10}g$
B) $3.7 \times 10^{- 10}g$
C) $6.25 \times 10^{- 34}g$
D) $1.438 \times 10^{- 11}g$
Explanation
(d) One curie $= 3.71 \times 10^{10}$ disintegrations $S\ ^{- 1}$
Mass of $6.023 \times 10^{23}$atoms of $U^{234} = 234\ g$
Mass of $3.71 \times 10^{10}$atoms
$= \frac{234 \times 3.71 \times 10^{10}}{6.023 \times 10^{23}} = 1.438 \times 10^{11}g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.