Q. The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is $v$. The velocity of an electron in its fifth orbit will be
A) $v$
B) $\frac{22}{5}v$
C) $\frac{5}{2}v$
D) $\frac{2}{5}v$
Explanation
(d) $v_{n} \propto \frac{1}{n} \Rightarrow \frac{v_{5}}{v_{2}} = \frac{2}{5} \Rightarrow v_{5} = \frac{2}{5}v_{2} = \frac{2}{5}v$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.