Q. In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential energy of the electron is
A) 1/2
B) 2
C) $- 1/2$
D) $- 2$
Explanation
(c) $K.E = \frac{kZe^{2}}{2r}$ and $P.E. = - \frac{kZe^{2}}{r};\ \therefore\frac{K.E.}{P.E.} = - \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.