(b) Number of atoms remains undecayed $N = N_{0}e^{- \lambda t}$
Number of atoms decayed $= N_{0}(1 - e^{- \lambda t})$
$= N_{0}\left( 1 - e^{- \lambda \times \frac{1}{\lambda}} \right) = N_{0}\left( 1 - \frac{1}{e} \right) = 0.63{\ N}_{0} = 63\%$ of $N_{0}$