(a) $R_{0} =$ Initial activity = 1 micro curie $= 3.7 \times 10^{4}d\ ps$
$r =$ Activity in $1\ cm^{3}$ of blood at $t = 5\ hr$
$= \frac{296}{60}dps = 4.93dps$
$R =$ Activity of whole blood at time $t = 5\ hr$
Total volume should be $V = \frac{R}{r} = \frac{R_{0}e^{- \lambda t}}{r}$
$= \frac{3.7 \times 10^{4} \times 0.7927}{4.93} = 5.94 \times 10^{3}cm^{3} = 5.94\ litre$