The radioactivity of a simple is $I_{1}$ at a time $t_{1}$ and $I_{2}$ at a time $t_{2}.$ If the half-life of the sample is$ au_{1/2}$,then the number of nuclei that have disintegrated in the time $t_{2} - t_{1}$ is proportional to

Question

The radioactivity of a simple is $I_{1}$ at a time $t_{1}$ and $I_{2}$ at a time $t_{2}.$ If the half-life of the sample is$	au_{1/2}$,then the number of nuclei that have disintegrated in the time $t_{2} - t_{1}$ is proportional to

Dr. Abubacker · Accepted Answer

(d) $\ \ \ \ \ \ \ \ \ \ \ T_{1/2} = \frac{0.693}{\lambda}$
Activity $I_{1}\  = \ N_{1}\lambda,\ \ \ I_{2} = \ N_{2}\lambda$
Let $\lambda$ = disintegration constant
$\ \ \ \ (I_{1} - I_{2})\  = \ (N_{1} - N_{2})\ \frac{0.693}{	au_{1/2}}$
$\ \ \ (N_{1} - N_{2}) \propto (I_{1} - I_{2})	au_{1/2}$

Q. The radioactivity of a simple is $I_{1}$ at a time $t_{1}$ and $I_{2}$ at a time $t_{2}.$ If the half-life of the sample is$\tau_{1/2}$,then the number of nuclei that have disintegrated in the time $t_{2} - t_{1}$ is proportional to

Explanation

Reviewed by Dr. Abubacker

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