Q. A nuclear transformation is denoted by $X$ ($n$,$\alpha) \rightarrow_{3}^{7}{Li}$. Which of the following is the nucleus of element $X$?
A) $_{6}^{12}C$
B) $_{5}^{10}B$
C) $_{5}^{9}B$
D) $_{4}^{11}{Be}$
Explanation
(b) $_{Z}^{A}X +_{0}^{1}n \rightarrow_{3}^{7}{Li} +_{2}^{4}{He}$
It implies that $A + 1 = 7 + 4$
$\Rightarrow$ $\ \ A = 10$
and $\ \ \ Z + 0 = 3 + 2$
$\Rightarrow$ $\ \ \ \ Z = 5$
Thus, it is boron$_{5}^{10}B$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.