Q. $16\ g$ sample of a radioactive element is taken from Bombay to Delhi in $2\ hour$ and it was found that $1\ g$ of the element remained (undisintegrated). Half life of the element is
A) $2\ hour$
B) $1\ hour$
C) $1/2\ hour$
D) $1/4\ hour$
Explanation
(c) $N = N_{0}\left( \frac{1}{2} \right)^{t/T_{1/2}} \Rightarrow 1 = 16\left( \frac{1}{2} \right)^{\frac{2}{T_{1/2}}} \Rightarrow T_{1/2} = \frac{1}{2}hour$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.