Q. The nucleus $\ _{6}C^{12}$absorbs an energetic neutron and emits a beta particle $(\beta)$. The resulting nucleus is
A) $\ _{7}N^{14}$
B) $\ _{5}B^{13}$
C) $\ _{7}N^{13}$
D) $\ _{6}C^{13}$
Explanation
(c) $\ _{6}C^{12} + \ _{0}n^{1} \longrightarrow \ _{Z}X^{A} + \ _{- 1}e^{0}$
$\therefore\ A = 12 + 1 = 13$
$Z = 6 + 1 = 7$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.