Q. The radioactive nucleus $\ _{7}N^{13}$ decays to $\ _{6}C^{13}$ through the emission of
A) Neutron
B) Proton
C) Electron
D) Positron
Explanation
(d) $\ _{7}N^{13} \rightarrow \ _{6}C^{13} +_{\ + 1}e^{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.