If the binding energy of the electron in a hydrogen atom is $13.6\ eV$, the energy required to remove the electron from the first excited state of $Li^{+ +}$ is

Question

Dr. Abubacker · Accepted Answer

(b) $E_{n} = \frac{13.6}{n^{2}} 	imes Z^{2}$. For first excited state $n = 2$ and for $Li^{+ +},z = 3 \Rightarrow E = \frac{13.6}{4} 	imes 9 = 30.6\ eV$

Q. If the binding energy of the electron in a hydrogen atom is $13.6\ eV$, the energy required to remove the electron from the first excited state of $Li^{+ +}$ is

Explanation

Reviewed by Dr. Abubacker

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