Q. The wavelength of Lyman series is
A) $\frac{4}{3 \times 10967}cm$
B) $\frac{3}{4 \times 10967}cm$
C) $\frac{4 \times 10967}{3}cm$
D) $\frac{3}{4} \times 10967cm$
Explanation
(a) $\frac{1}{\lambda} = R_{H}\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack$. For Lyman series $n_{1} = 1$ and $n_{2} = 2,3,4\ldots$
When $n_{2} = 2$, we get $\lambda = \frac{4}{3R_{H}} = \frac{4}{3 \times 10967}cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.