The truth table given below is for ($A$ and $B$ are the inputs, $Y$ is the output) [table] $\mathbf{A}$ | $\mathbf{B}$ | $\mathbf{Y}$ ; $0$ $0$ $1$ $1$ | $0$ $1$ $0$ $1$ | $1$ $1$ $1$ $0$ [/table]

Question

Dr. Abubacker · Accepted Answer

(d) The output $\ Y$ is a combination of AND + NOT gate. Hence, the truth table is for NAND gate.

Q. The truth table given below is for ($A$ and $B$ are the inputs, $Y$ is the output) [table] $\mathbf{A}$ | $\mathbf{B}$ | $\mathbf{Y}$ ; $0$ $0$ $1$ $1$ | $0$ $1$ $0$ $1$ | $1$ $1$ $1$ $0$ [/table]

Explanation

Reviewed by Dr. Abubacker

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