Q.
The combination of ‘NAND’ gates shown here under figure, are equivalent to
A) An OR gate and an AND gate respectively
B) An AND gate and a NOT gate respectively
C) An AND gate and an OR gate respectively
D) An OR gate and a NOT gate respectively
Explanation
(a) For first case, the Boolean expression is, $Y = \overline{\overline{A} \bullet \overline{B}} = A + B$ hence for OR gate and for second case, the Boolean expression is $Y = \overline{\overline{A} \bullet \overline{B}} = A \bullet B$, hence for AND gate.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.