(c) Hence, (10111)$B = {1 \times 2}^{4} + {0 \times 2}^{3} + {1 \times 2}^{2} + {1 \times 2}^{1} + {1 \times 2}^{0}$ = 16 + 0 + 4 + 2 + 1 = 23
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