Q. What is the current in the circuit shown below
A) 0 $A$
B) $10^{- 2}\ A$
C) 1 $A$
D) 0.10 $A$
Explanation
(a) The potential of $P$-side is more negative that of $N$-side, hence diode is in reverse biasing. In reverse biasing it acts as open circuit, hence no current flows
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.