Q. A junction diode is connected to a 10 V source and $10^{3}\Omega$ rheostate figure. The slope of load line on the characteristic curve of diode will be
A) $10^{- 2}AV^{- 1}$
B) $10^{- 3}AV^{- 1}$
C) $10^{- 4}AV^{- 1}$
D) $10^{- 5}AV^{- 1}$
Explanation
(b) If $V$ is the voltage across the junction and $I$ is the circuit current, then
$V + IR = E$
or $I = \frac{E}{R} - \frac{V}{R} = - \frac{V}{R} + \frac{E}{R}$
Slope of load line$\ = - \frac{1}{R} = \frac{1}{1000} = 10^{- 3}AV^{- 1}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.