Q. The grid voltage of any triode valve is changed from $- 1\ volt$ to $- 3\ volt$ and the mutual conductance is $3 \times 10^{- 4}\ mho$. The change in plate circuit current will be
A) $0.8\ mA$
B) $0.6\ mA$
C) $0.4\ mA$
D) $1\ mA$
Explanation
(b) By using $g_{m} = \frac{\mathrm{\Delta}i_{p}}{\mathrm{\Delta}v_{g}} \Rightarrow 3 \times 10^{- 4} = \frac{\mathrm{\Delta}i_{p}}{- 1 - ( - 3)}$
$\Rightarrow \mathrm{\Delta}i_{p} = 6 \times 10^{- 4}A = 0.6\ mA$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.