Q. The resonance frequency of the tank circuit of an oscillator when $L = \frac{10}{\pi^{2}}mH$ and $C = 0.04\mu\ F$ are connected in parallel is
A) 250 $kHz$
B) 25 $kHz$
C) 2.5 $kHz$
D) 25 $MHz$
Explanation
(b) $v = \frac{1}{2\pi\sqrt{LC}} = \frac{1}{2\pi}\frac{1}{\sqrt{\frac{10}{\pi^{2}} \times 10^{- 3} \times 0.04 \times 10^{- 6}}}$
$= 25\ kH_{Z}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.