Q.
What is the current through an ideal PN-junction diode shown in figure below
A) Zero
B) 10 $mA$
C) 20 $mA$
D) 50 $mA$
Explanation
(c) The potential of $N$-Side is more negative than that of $P$-Side, hence diode is in forward biasing from circuit resultant potential is $2V$
$\therefore I = \frac{2}{100} = 20\ mA$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.