Q. The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm, is incident on it. The band gap in (eV) for the semiconductor is

A) 1.1 eV
B) 2.5 eV
C) 0.5 eV
D) 0.7 eV
Explanation

(c) $E_{g} = h$v =$\frac{hc}{\lambda} = \left( \frac{{6.63 \times 10}^{- 34} \times {3 \times 10}^{8}}{{2480 \times 10}^{- 9} \times {1.6 \times 10}^{- 19}} \right) = 0.5$ eV

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.