(c) $E_{g} = h$v =$\frac{hc}{\lambda} = \left( \frac{{6.63 \times 10}^{- 34} \times {3 \times 10}^{8}}{{2480 \times 10}^{- 9} \times {1.6 \times 10}^{- 19}} \right) = 0.5$ eV
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.