Q.
The current in the circuit shown in the figure, considering ideal diode is
A) 20 A
B) ${2 \times 10}^{- 3}$ A
C) 200 A
D) ${2 \times 10}^{- 4}$ A
Explanation
(b) Potential difference across diode
= 3.2 $–$ 3 = 0.2 V
$\therefore$ Current through diode
$i = \frac{0.2}{100} = {2 \times 10}^{- 3}$ A
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.