Q. The current gain of a common base transistor circuit is 0.96. On changing the emitter current by 10.0 mA, the change in the base current will be
A) 9.6 mA
B) 0.4 mA
C) 19.6 mA
D) 24 mA
Explanation
(a) Current gain for common base transistor
$\alpha = \left( \frac{\mathrm{\Delta}I_{c}}{\mathrm{\Delta}I_{e}} \right)_{Ve}$
Given, $\alpha = 0.96,\ \mathrm{\Delta}I_{E} = 10.0\ mA$
0.96 = $\frac{\mathrm{\Delta}I_{c}}{10}$
$\mathrm{\Delta}I_{c} = 0.96 \times 10 = \ $9.6 mA
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.