Q. The amplification factor of a triode valve is 15. If the grid voltage is changed by $0.3\ volt$ the change in plate voltage in order to keep the plate current constant (in volt) is
A) 0.02
B) 0.002
C) 4.5
D) 5.0
Explanation
(c) $\mu = \frac{\mathrm{\Delta}V_{p}}{\mathrm{\Delta}V_{g}} \Rightarrow \mathrm{\Delta}V_{p} = \mu\mathrm{\Delta}V_{g} = 15 \times 0.3 = 4.5\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.