Q. The resistance of a germanium junction diode whose $V - I$ is shown in figure is $(V_{k} = 0.3\ V)$
A) 5 $k\Omega$
B) $0.2\ k\Omega$
C) $2.3\ k\Omega$
D) $\left( \frac{10}{2.3} \right)k\Omega$
Explanation
(b) $V_{k} =$ knee voltage $= 0.3\ V$
$\therefore$ Resistance $= \frac{\mathrm{\Delta}V}{\mathrm{\Delta}i} = \frac{(2.3 - 0.3)}{(10 - 0) \times 10^{- 3}} = 200\Omega = 0.2k\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.