Q. The depletion layer in a silicon diode is 1 $\mu$m wide and its knee potential is 0.6 V, then the electric field in the depletion layer will be
A) 0.6 ${Vm}^{- 1}$
B) ${6 \times 10}^{4}$ ${Vm}^{- 1}$
C) ${6 \times 10}^{5}$ ${Vm}^{- 1}$
D) Zero
Explanation
(c) $E = - \frac{dV}{dr} = \frac{0.6}{10^{- 6}} = {6 \times 10}^{5}$ ${Vm}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.