(d) Given circuit, $V_{r_{2}} = 10\ V\ and\ I_{r_{2}} = 6.67\ mA$ $I_{r_{1}} = \frac{5}{500}$ = 10 mA $\therefore I$$_{2}$ = 10 $- \ 6.67 = 3.33$ mA
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Ph.D. in Physics with 19+ years of teaching experience.