A common emitter amplifier is designed with $NPN$ transistor $(\alpha = 0.99)$. The input impedance is $1\ K\Omega$ and load is $10\ K\Omega$. The voltage gain will be

Question

Dr. Abubacker · Accepted Answer

(c) Voltage gain $= \beta 	imes$ Resistance gain
$\beta = \frac{\alpha}{1 - \alpha} = \frac{0.99}{(1 - 0.99)} = 99$
Resistance gain $= \frac{10 	imes 10^{3}}{10^{3}} = 99$
$\Rightarrow$ Voltage gain $= 99 	imes 10 = 990$

Q. A common emitter amplifier is designed with $NPN$ transistor $(\alpha = 0.99)$. The input impedance is $1\ K\Omega$ and load is $10\ K\Omega$. The voltage gain will be

Explanation

Reviewed by Dr. Abubacker

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