Q. When the plate voltage of a triode is 150V, its cut-off voltage is $- 5$ V. On increasing the plate voltage to 200 V, the cut-off voltage can be
A) $- 4.5\ V$
B) $- 5.0\ V$
C) $- 2.3\ V$
D) $- 6.66\ V$
Explanation
(d) $V_{g_{2}} = V_{g_{1}}\left( \frac{V_{p_{2}}}{V_{p_{1}}} \right) = - 5\left( \frac{200}{150} \right) = - 6.66\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.