Q. The decimal equivalent of the binary number $(11010.101)_{2}$ is

A) 9.625
B) 25.265
C) 26.625
D) 26.265
Explanation

(c) $(11010.101) = 1 \times 2^{4} + 1 \times 2^{3} + 0 \times 2^{2} +$
$1 \times 2^{1} + 0 \times 2^{0} + 1 \times 2^{- 1}\ +$
$0 \times 2^{- 2} + 1 \times 2^{- 3}$
$= 16 + 8 + 0 + 2 + 0 + \frac{1}{2} + 0 + \frac{1}{8} = 26 + \frac{1}{2} + \frac{1}{8}$
$= 26\frac{5}{8} = 26.625$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.