Q. In a common emitter transistor, the current gain is 80. What is the change in collector current, when the change in base current is $250\ \mu A$
A) $80 \times 250\ \mu A$
B) $(250 - 80)\mu A$
C) $(250 + 80)\mu A$
D) $250/80\ \mu A$
Explanation
(a) Current gain $\beta = \frac{\mathrm{\Delta}i_{c}}{\mathrm{\Delta}i_{b}} \Rightarrow \mathrm{\Delta}i_{c} = \beta \times \mathrm{\Delta}i_{b} = 80 \times 250\ \mu A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.