Q.
To get an output 1 from the circuit shown in the figure, the input must be
A) $A = 0,B = 1,C = 0$
B) $A = 1,B = 0,C = 0$
C) $A = 1,B = 0,C = 1$
D) $A = 1,B = 1,C = 0$
Explanation
(c) We can realize the gate circuit as
[image:14_image219.jpeg]
Output of gate 1, $Y_{1} = A + B$
Output of gate 2, $Y_{2} = Y_{1} \bullet C = (A + B) \bullet C$
(a) If $A = 0,B = 1,C = 0,$ then
$Y_{2} = (0 + 1) \bullet 0 = 1 \bullet 0 = 0$
(b) If $A = 1,B = 0,C = 0,$ then
$Y_{2} = (1 + 0) \bullet 0 = 1 \bullet 0 = 0$
(c) If $A = 1,B = 0,C = 1,$ then
$Y_{2} = (1 + 0) \bullet 1 = 1 \bullet 1 = 1$
(d) If $A = 1,B = 1,C = 0,$ then
$Y_{2} = (1 + 1) \bullet 0 = 1 \bullet 0 = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.