Q. In the network show, the current flowing through the battery of negligible internal resistance is
A) 0.10 A
B) 0.15 A
C) 0.20 A
D) 0.30 A
Explanation
(b) The upper junction diode is forward biased and middle junction diode is reverce biased. So, effective resistance of circuit$= 10 + 10 = 20\ \Omega.$
$I = \frac{3}{20} = 0.15\ A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.