Q.
The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 milli-watt. What should be the value of the resistance$\ R$, connected in series with the diode, for obtaining maximum current?
A) 1.5 $\Omega$
B) 5 $\Omega$
C) 6.67 $\Omega$
D) 200 $\Omega$
Explanation
(b) $R = \frac{Voltage\ drop}{Current}$
$\therefore$ Current in circuit, $I = \frac{P}{V} = \frac{{100 \times 10}^{- 3}}{0.5} = 0.2$ A
$R = \frac{1}{0.2} = 5\ \Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.