Q.
The combination of gates shown below yields
A) OR gate
B) NOT gate
C) XOR gate
D) NAND gate
Explanation
(a) Truth table for given combination is
[table] $\mathbf{A}$ | $\mathbf{B}$ | $\mathbf{X}$ ; $0$ $0$ $1$ $1$ | $0$ $1$ $0$ $1$ | $0$ $1$ $1$ $1$ [/table]
This comes out to be truth table of OR gate.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.