Q. In the following common emitter configuration an $NPN$ transistor with current gain $\beta = 100$ is used. The output voltage of the amplifier will be
A) 10 $mV$
B) 0.1 $V$
C) 1.0 $V$
D) 10 $V$
Explanation
(c) Voltage gain $= \frac{Output\ voltage}{Input\ voltage}$
$\Rightarrow V_{out} = V_{in} \times$ Voltage gain
$\Rightarrow V_{out} = V_{in} \times$ Current gain $\times$ Resistance gain
$= V_{in} \times \beta \times \frac{R_{L}}{R_{BE}} = 10^{- 3} \times 100 \times \frac{10}{1} = 1V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.