Q. In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5\ volt$. The collector current changes by $0.05\ mA$. The output resistance will be
A) 10 $k\Omega$
B) 20 $k\Omega$
C) 5 $k\Omega$
D) 2.5 $k\Omega$
Explanation
(a) Here $\mathrm{\Delta}V_{c} = 0.5\ V,\ \mathrm{\Delta}i_{c} = 0.05mA = 0.05 \times 10^{- 3}A$
Output resistance is given by
$R_{out} = \frac{\mathrm{\Delta}V_{c}}{\mathrm{\Delta}i_{c}} = \frac{0.5}{0.05 \times 10^{- 3}} = 10^{4}\Omega = 10k\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.