Q.
A junction diode has a resistance of $25\ \Omega$ when forward biased and $2500\ \Omega$ when reverse biased. The current in the diode, for the arrangement shown will be
A) $\frac{1}{15}A$
B) $\frac{1}{7}A$
C) $\frac{1}{25}A$
D) $\frac{1}{480}A$
Explanation
(b) For forward bias, $I = \frac{V}{R} = \frac{5}{25 + 10} = \frac{5}{35} = \frac{1}{7}A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.