Q. The reverse bias in a junction diode is changed from 8 V to 13 V then the value of the current charges from $40\ \mu A\ to\ 60\ \mu A$. The resistance of junction diode will be
A) $2 \times 10^{5}\Omega$
B) $2.5 \times 10^{5}\Omega$
C) $3 \times 10^{5}\Omega$
D) $4 \times 10^{5}\Omega$
Explanation
(b) $R_{e} = \frac{\mathrm{\Delta}V}{\mathrm{\Delta}I} = \frac{(13 - 8)}{(60 - 40) \times 10^{- 6}} = 2.5 \times 10^{5}\Omega.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.