Q.
Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is
A) 0.75 $A$
B) Zero
C) 0.25 $A$
D) 0.5 $A$
Explanation
(d) Here $D_{1}$ is in forward bias and $D_{2}$ is in reverse bias so
$I = \frac{V}{R} = \frac{5}{10} = \frac{1}{2}Amp$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.