(c) Voltage gain $= \frac{V_{out}}{V_{in}} = \frac{\mu}{1 + \frac{r_{p}}{R_{L}}} \Rightarrow \frac{V_{out}}{0.05} = \frac{25}{1 + \frac{40 \times 10^{3}}{10 \times 10^{3}}}$ $\Rightarrow V_{out} = 2.5\ V$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.