Q. In circuit in following fig. the value of $Y$ is
A) 0
B) 1
C) Fluctuates between 0 and 1
D) Indeterminate as the circuit can’t be realised
Explanation
(a) Lower NOT gate inverts input to zero. NOT gate from NAND gate inverts this output to 1 upper NAND gate converts this input 1 and input 0 to 1.
Thus $A = 1$ and $B = 1$ become inputs of NAND gate giving final output as zero. Choice $A$ is correct
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.