(b) In circuit 1, $N$ is connected with $N$, which is not a series combination of $p - n$ junction. In circuit 2, each $p - n$ junction is forward biased, hence same current flows, giving same potential difference across $p - n$ junction. In circuit 2, each $p - n$ junction is reverse biased, same leakage current will flow, giving equal potential difference across each $p - n$ junction diode.