Q. Consider the junction diode is ideal. The value of current in the figure is
A) Zero
B) $10^{- 2}A$
C) $10^{- 1}A$
D) $10^{- 3}A$
Explanation
(b) $I_{f} = \frac{4 - 1}{300} = \frac{1}{100} = 10^{- 2}A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.