Explanation

(b) In reverse biasing, the applied voltage $V$ on the $n$-side is positive and is negative on the $p$-side. The applied bias $V$ and the barrier potential $V_{B}$ are in the same direction making the effective junction potential ${V + V}_{B}$. As a result, the junction width will increase. The higher junction potential would restrict the flow of majority carriers to a much greater extent. However, such a field will favour the flow of minority carriers. So, reverse bias current will be due to the minority carriers only.
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