Q. A diode having potential difference 0.5 V across its junction which does not depend on current, is connected in series with resistance of 20$\Omega$ across source. If 0.1 A current passes through resistance then what is the voltage of the source?
A) 1.5 V
B) 2.0 V
C) 2.5 V
D) 5 V
Explanation
(c) The circuit diagram of the given situation is shown. Since, it is a closed mesh, the voltage is
$V = V^{'} + IR$
[image:14_image240.emf]
Given, $V^{'} = 0.5\ V,\ I = 0.1\ A,\ R = 20\Omega$
$I = 0.5 + 0.1 \times 20$
$V = 2.5$ volt
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.