Q. In a common-base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor ($\beta$) will be
A) 49
B) 50
C) 51
D) 48
Explanation
(a) $\beta = \frac{I_{C}}{I_{B}}$ and $I_{E} = I_{C} + I_{B}$
$\therefore = \frac{I_{C}}{I_{E} - I_{C}} = \frac{5.488}{5.60 - 5.488} = 49$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.