Q. The equivalent decimal number of binary number $(11001.001)_{2}$ is
A) 19.100
B) 19.050
C) 25.250
D) 25.125
Explanation
(d) $(11001.001)_{2} = 1 \times 2^{0} + 0 \times 2^{1} + 0 \times 2^{2} + 1 \times 2^{3} + 1 \times 2^{4} + 0 \times 2^{- 1} + 0 \times 2^{- 2} + 1 \times 2^{- 3} = 25.125$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.