In the circuit shown below, an input of $1V$ is fed into the inverting input of an ideal OP-amplifier. The output signal $V_{out}$ will be [image:14_image139.emf]

Question

Dr. Abubacker · Accepted Answer

(b) This is operational or OP-inverting amplifier
$A = \frac{V_{0}}{V_{i}} = - \frac{R_{f}}{R_{i}}$
Given $V_{i} = 1V,\ R_{f} = 10k\Omega,\ R_{i} = 1k\Omega$
$	herefore V_{0} = - V_{i}\frac{R_{f}}{R_{i}} = - 1 	imes \frac{10}{1} \Rightarrow V_{0} = - 10\ V$
$V_{0}$ is negative because $V_{input}$ is $+ 1V$ (positive)

Q. In the circuit shown below, an input of $1V$ is fed into the inverting input of an ideal OP-amplifier. The output signal $V_{out}$ will be

Explanation

Reviewed by Dr. Abubacker

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