Q. In a common emitter transistor amplifier $\beta = 60,\ R_{0} = 5000\Omega$ and internal resistance of a transistor is $500\Omega$. The voltage amplification of amplifier will be

A) 500
B) 460
C) 600
D) 560
Explanation

(c) $A_{V} = \beta\frac{R_{0}}{R_{i}} = 60 \times \frac{5000}{500} = 600.$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.